• Soal ada di gambar
• Mohon dengan cara atau langkah - langkah
No. 1
Jawaban:
1) R = V / I
R = 2 / 0,5
R = 4 Ohm
2) R = V / I
R = 4 / 1
R = 4 Ohm
3) R = V / I
R = 6 / 1,5
R = 4 Ohm
4) R = V / I
R = 8 / 2
R = 4 Ohm
5) R = 10 / 2,5
R = 4 Ohm
No. 2
Diketahui:
(KONDISI 1)
Q1a = q
Q2a = q
Ra = r
(KONDISI 2)
Rb = 1/2r
Jawaban:
Fa : Fb = k . Q1 . Q2 / r² : k . Q1 . Q2 / r²
Fa : Fb = q . q / r² : q . q / (1/2r)²
Fa : Fb = 1 / r² : 1 / (1/4r²)
Fa : Fb = 1 : 1 / (1/4)
Fa : Fb = 1 : 4
soal latihan kelas 9
1. R = V/I
R = 2/0,50
R = 4 Ohm
b. R = V/I
R = 4/1,00
R = 4 Ohm
c. R = V/I
R = 6/1,50
R = 9 Ohm
d. R = V/I
R = 8/2,00
R = 4 Ohm
e. R = V/I
R = 10/2,50
R = 4 Ohm
soal nomor 2 :
diketahui :
r1 = r
r2 = ½ r
ditanya :
perbandingan gaya Coulomb?
Jawab :
F1/F2 = (r2)²/(r1)²
F1/F2 = ¼r²/r²
F1/F2 = ¼ : 1
F1/F2 = ¼
F1 : F2 = 1 : 4
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